document.write( "Question 55662: To avoid hitting the ball out, a tennis player in one corner of the 312 yd squared court hits the ball to the farthest corner of the opponent
\n" ); document.write( "s court. If the length, L, of the tennis court is 2 yd. longer than twice the width, then how far did the player hit the ball? \n" ); document.write( "
Algebra.Com's Answer #37771 by stanbon(75887)\"\" \"About 
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To avoid hitting the ball out, a tennis player in one corner of the 312 yd squared court hits the ball to the farthest corner of the opponent
\n" ); document.write( "s court. If the length, L, of the tennis court is 2 yd. longer than twice the width, then how far did the player hit the ball?
\n" ); document.write( "---------
\n" ); document.write( "Let the width be \"w\".
\n" ); document.write( "Then the length = 2w+2
\n" ); document.write( "Area = w(2w+2)=2w^2+2w=312
\n" ); document.write( "Divide thru by 2 to get:
\n" ); document.write( "w^2+w-156=0
\n" ); document.write( "(w+13)(w-12)=10
\n" ); document.write( "width = 12 yrds.
\n" ); document.write( "Length = 2(12)+2=26 yrds
\n" ); document.write( "Use Pythagoras to find the diagonal distance:
\n" ); document.write( "d=sqrt(12^2+26^2)
\n" ); document.write( "d=sqrt820
\n" ); document.write( "distance = 28.64 yrds.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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