document.write( "Question 596354: Air Pollution the amount of mitrogen dioxide A in parts per million (PPM) that presetn in the air in the city of homer on a certain day in june is modeled by the function a(t)=-2t^2+32t+12
\n" );
document.write( "Where t is the number of hours after 6:00 am use this function to find the time at which the nitrogen dioxide level was at its maximum. \n" );
document.write( "
Algebra.Com's Answer #377693 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Air Pollution the amount of mitrogen dioxide A in parts per million (PPM) that presetn in the air in the city of homer on a certain day in june is modeled by the function a(t)=-2t^2+32t+12 \n" ); document.write( " Where t is the number of hours after 6:00 am use this function to find the time at which the nitrogen dioxide level was at its maximum. \n" ); document.write( ". \n" ); document.write( "Because the coefficient associated with the t^2 term is negative, we KNOW that it is a parabola that opens downwards. So, the vertex is the max. \n" ); document.write( ". \n" ); document.write( "t-value at max: \n" ); document.write( "t = -b/(2a) \n" ); document.write( "t = -32/(2(-2)) \n" ); document.write( "t = -32/(-4) \n" ); document.write( "t = 8 hours \n" ); document.write( ". \n" ); document.write( "6:00 am + 8 hours = 2 pm\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |