document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=596242>Question 596242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let A be an angle in which cosA = square root 2/2<BR>\n" );
document.write( "What is cot A </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #377616 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=377616\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A be an angle in which cosA = square root 2/2<BR>\n" );
document.write( "What is cot A<BR>\n" );
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document.write( "A could be in Q1 or Q4.<BR>\n" );
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document.write( "Since cos = x/r = Sqrt(2)/2, x = sqrt(2) and r = 2<BR>\n" );
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document.write( "Then y = sqrt(r^2-x^2) = sqrt(4+2) = sqrt(6) in Q1 and -sqrt(6) in Q4.<BR>\n" );
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document.write( "In Q1: cot(A) = x/y = sqrt(2)/sqrt(6)<BR>\n" );
document.write( "In Q4: cot(A) = x/y = -[sqrt(2)/sqrt(6)]<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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