document.write( "Question 596172: Solve 8^(x+8) = 32^x
\n" ); document.write( "The lesson this is found is called Exponential and Logarithmic Equations
\n" ); document.write( "I am looking for more of the steps on how to complete rather then the answer but both would be great. Thanks for your help \r
\n" ); document.write( "\n" ); document.write( "The steps I have tried are
\n" ); document.write( "8 ^(x+8) = 32^x ( Original Problem)\r
\n" ); document.write( "\n" ); document.write( "log 8^(x+8)= log 32^x
\n" ); document.write( "
\n" ); document.write( "(x+8) log 8 = x log 32\r
\n" ); document.write( "\n" ); document.write( "(log8)x +8log8 = (log 32)x\r
\n" ); document.write( "\n" ); document.write( "8log8 = x log 32- x log 8\r
\n" ); document.write( "\n" ); document.write( " 8log8 = x log 24
\n" ); document.write( "

Algebra.Com's Answer #377563 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
The steps I have tried are
\n" ); document.write( "8 ^(x+8) = 32^x ( Original Problem)
\n" ); document.write( "log 8^(x+8)= log 32^x\r
\n" ); document.write( "\n" ); document.write( "(x+8) log 8 = x log 32
\n" ); document.write( "(log8)x + 8log8 = (log 32)x
\n" ); document.write( "8log8 = x log 32- x log 8
\n" ); document.write( "8log8 = x log 24 ********* That's not right
\n" ); document.write( "---------------------------
\n" ); document.write( "8log8 = x log 32- x log 8
\n" ); document.write( "8log8 = x*(log 32 - log 8)
\n" ); document.write( "8lob(8) = x*log(4) Subtracting logs is division
\n" ); document.write( "x = 8log(8)/log(4)
\n" ); document.write( "x = 12
\n" ); document.write( "-----------------
\n" ); document.write( "A better way:
\n" ); document.write( "8 ^(x+8) = 32^x
\n" ); document.write( "8 = 2^3 and 32 = 2^5
\n" ); document.write( "\"2%5E%283x%2B24%29+=+2%5E%285x%29\"
\n" ); document.write( "3x+24 = 5x
\n" ); document.write( "2x + 24
\n" ); document.write( "x = 12
\n" ); document.write( "
\n" ); document.write( "
\n" );