document.write( "Question 596105: 10 Men begin to work together on a job, but after some days, 4 of them left the job. As a
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document.write( "result the job which could have been completed in 40 days is completed in 50 days. How
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document.write( "many days after the commencement of the work did the 4 men leave?
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document.write( "(a) 25 (b) 30 (c) 10 (d) 15 \n" );
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Algebra.Com's Answer #377556 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! This says that 10 men could have done the job \n" ); document.write( "in 40 days. \n" ); document.write( "1 man would have taken 10 times as long, so \n" ); document.write( "1 man does the job in 400 days \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "----------------- \n" ); document.write( "In general, ( rate of working for 1 man ) x ( number of men ) x ( number of days ) = part of job completed \n" ); document.write( "( 1 job / 400 days ) x ( 10 men ) x ( n days ) = part of job completed \n" ); document.write( "( 1 job / 400 days ) x ( 6 men ) x ( 50 - n days ) = part of job completed \n" ); document.write( "The 2 parts add up to 1 job completed \n" ); document.write( "----------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The 4 men left 25 days after the work started \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |