document.write( "Question 596129: When dealing with the quadratic equation f(x)=-0.2x^2+12x+11, where the function represents the expected number of ticket sales each day, and x=1 is the day tickets go on sale.
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document.write( "My main question is, using this equation how can I determine the last day that tickets will be sold? \n" );
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Algebra.Com's Answer #377534 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! f(x)=-0.2x^2+12x+11 \n" ); document.write( "since f(x) represents the number of tickets sold \n" ); document.write( "to find the last day tickets were sold, set f(x) to zero and solve for x: \n" ); document.write( "f(x)=-0.2x^2+12x+11 \n" ); document.write( "0=-0.2x^2+12x+11 \n" ); document.write( "0=0.2x^2-12x-11 \n" ); document.write( "applying the quadratic formula, we get: \n" ); document.write( "x = {60.9, -0.9} \n" ); document.write( "we can toss out the negative solution (extraneous) leaving: \n" ); document.write( "x = 60 days \n" ); document.write( ". \n" ); document.write( "details of quadratic follows: \n" ); document.write( "
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