document.write( "Question 596126: Please, Please, Please can someone help me to solve this equation. I am so confused. Thank you for your quick response!\r
\n" );
document.write( "\n" );
document.write( "W = 33 – (10.45 + 10√(v-v) ) (33-T)
\n" );
document.write( " a. T = 10c; v = 9m/sec
\n" );
document.write( " b. T= 0c; v = 15m/sec
\n" );
document.write( " c. T=-10c, v=20/sec\r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #377525 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! (I would encourage you to not use the \"check mark\" symbol in the future. On algebra.com use \"sqrt(...)\" for square roots. :sqrt\" is not standard notation in Math but think every tutor on algebra.com will understand it. And the parentheses makes it clear what is inside the square root.) \n" ); document.write( " \n" ); document.write( "a. T = 10c; v = 9m/sec: \n" ); document.write( "I'm assuming that the \"c\" means Celcius/Centigrade. \n" ); document.write( " \n" ); document.write( "Replacing the square root of the perfect square, 9: \n" ); document.write( " \n" ); document.write( "Now you just simplify (according to PEMDAS, of course). Inside the first parentheses we multiply first: \n" ); document.write( " \n" ); document.write( "Adding/subtracting the like terms in both sets of parentheses: \n" ); document.write( " \n" ); document.write( "Multiply: \n" ); document.write( "W = 33 - 723.35 \n" ); document.write( "Subtracting: \n" ); document.write( "W = -690.35 \n" ); document.write( "What does \"W\" represent? Is it possible for it to have a negative value? If not, then the equation is still incorrect. \n" ); document.write( "I'm going to skip part b and go on to part c. After seeing parts a and c solved I hope you will be able to do part b on your own. \n" ); document.write( "c. T=-10c, v=20/sec \n" ); document.write( " \n" ); document.write( "This time the square root does not turn into a whole number (since 20 is not a perfect square). But it will simplify: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " Adding/subtracting the like terms in both sets of parentheses: \n" ); document.write( " \n" ); document.write( "Distribute the 43: \n" ); document.write( " \n" ); document.write( "Subtract the expression in the parentheses: \n" ); document.write( " \n" ); document.write( "Adding like terms: \n" ); document.write( " \n" ); document.write( "This is an exact expression for the answer. For a decimal approximation of the answer, then we need to use a calculator on the square root: \n" ); document.write( "W = 443.65 - 860*2.23606798 \n" ); document.write( "Multiply: \n" ); document.write( "W = 443.65 - 1923.01846065 \n" ); document.write( "Subtract: \n" ); document.write( "W = -1479.36846065 \n" ); document.write( "So W is approximately -1480. \n" ); document.write( "I hope that from parts a & c you are now able to do part b on your own. \n" ); document.write( " |