document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55646>Question 55646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> b/4ab+3b/4ab Please help simpilfy\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37749 by </B><A HREF=/tutors/aboutme.mpl?userid=JayJay_T><B>JayJay_T(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JayJay_T><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37749\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok, this is not thát hard:<BR>\n" );
document.write( "We have to add 2 fractions with equal denominator (4ab). <BR>\n" );
document.write( "This means the solution will be of a type x/4ab. Let's add-up:<BR>\n" );
document.write( "b + 3b = 4b, givin' us the 'x'-value.\r<BR>\n" );
document.write( "\n" );
document.write( "We now have 4b/4ab. \r<BR>\n" );
document.write( "\n" );
document.write( "This we can simplify a bit more: 4b is present in the numerator ás in the denominator (4b/4ba) leaving us with the solution: \r<BR>\n" );
document.write( "\n" );
document.write( "1/a<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );