document.write( "Question 596063: Please help me solve the problem:
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Algebra.Com's Answer #377481 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"12c%5E2%2B8c%2B1=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"12c%5E2%2B8c%2B1\" is in the form of \"Ac%5E2%2BBc%2BC\" where \"A=12\", \"B=8\", and \"C=1\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"c\":\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-%288%29+%2B-+sqrt%28+%288%29%5E2-4%2812%29%281%29+%29%29%2F%282%2812%29%29\" Plug in \"A=12\", \"B=8\", and \"C=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-8+%2B-+sqrt%28+64-4%2812%29%281%29+%29%29%2F%282%2812%29%29\" Square \"8\" to get \"64\". \r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-8+%2B-+sqrt%28+64-48+%29%29%2F%282%2812%29%29\" Multiply \"4%2812%29%281%29\" to get \"48\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-8+%2B-+sqrt%28+16+%29%29%2F%282%2812%29%29\" Subtract \"48\" from \"64\" to get \"16\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-8+%2B-+sqrt%28+16+%29%29%2F%2824%29\" Multiply \"2\" and \"12\" to get \"24\". \r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-8+%2B-+4%29%2F%2824%29\" Take the square root of \"16\" to get \"4\". \r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-8+%2B+4%29%2F%2824%29\" or \"c+=+%28-8+-+4%29%2F%2824%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-4%29%2F%2824%29\" or \"c+=++%28-12%29%2F%2824%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"c+=+-1%2F6\" or \"c+=+-1%2F2\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"c+=+-1%2F6\" or \"c+=+-1%2F2\" \r
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