document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=595991>Question 595991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A area of a equilateral triangle with a side length of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8sqrt%283%29 ALIGN=MIDDLE  ALT=\"8sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #377445 by </B><A HREF=/tutors/aboutme.mpl?userid=math-vortex><B>math-vortex(648)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math-vortex><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math-vortex><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=377445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi, there---<BR>\n" );
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document.write( "In order to find the area of a triangle we need to know the base B and the height H. Then we use the formula for the area of a triangle, A=BH/2.<BR>\n" );
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document.write( "[I] Find the base<BR>\n" );
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document.write( "By definition, the sides of an equilateral triangle are the same, so our base is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8sqrt%283%29 ALIGN=MIDDLE  ALT=\"8sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "[II] Find the height<BR>\n" );
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document.write( "If we draw a line segment for the height of the equilateral triangle, we see that it divides the triangle into two congruent 30-60-90 degree right triangles. The hypotenuse of the 30-60-90 triangle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8sqrt%283%29 ALIGN=MIDDLE  ALT=\"8sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Its base is half the length of the hypotenuse, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4sqrt%283%29 ALIGN=MIDDLE  ALT=\"4sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and the height of the  other leg is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sqrt%283%29%29%2F2 ALIGN=MIDDLE  ALT=\"%28sqrt%283%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > times the hypotenuse, or 12.<BR>\n" );
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document.write( "[III] Find the area<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=%281%2F2%29%28B%29%28H%29 ALIGN=MIDDLE  ALT=\"A=%281%2F2%29%28B%29%28H%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=%281%2F2%29%284sqrt%283%29%29%2812%29 ALIGN=MIDDLE  ALT=\"A=%281%2F2%29%284sqrt%283%29%29%2812%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=24sqrt%283%29 ALIGN=MIDDLE  ALT=\"A=24sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "That's it! Feel free to email if any part of the explanation doesn't make sense.<BR>\n" );
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document.write( "Mrs.Figgy<BR>\n" );
document.write( "math.in.the.vortex@gmail.com<BR>\n" );
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