document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=596025>Question 596025</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many 2/3 acres lots can fill a 9 3/4 acres of land? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #377437 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=377437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = # of lots\r<BR>\n" );
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document.write( "If each lot is 2/3 of an acre, then x lots will be total of (2/3)x acres\r<BR>\n" );
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document.write( "We want this to be 9 3/4, so...\r<BR>\n" );
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document.write( "(2/3)x = 9  3/4\r<BR>\n" );
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document.write( "(2/3)x = 9 + 3/4\r<BR>\n" );
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document.write( "(2/3)x = 36/4 + 3/4\r<BR>\n" );
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document.write( "(2/3)x = 39/4\r<BR>\n" );
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document.write( "2x = 3*(39/4)\r<BR>\n" );
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document.write( "2x = 117/4\r<BR>\n" );
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document.write( "x = (117/4)/2\r<BR>\n" );
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document.write( "x = (117/4)*(1/2)\r<BR>\n" );
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document.write( "x = 117/8\r<BR>\n" );
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document.write( "x = (112 + 5)/8\r<BR>\n" );
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document.write( "x = 112/8 + 5/8\r<BR>\n" );
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document.write( "x = 14 + 5/8\r<BR>\n" );
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document.write( "x = 14  5/8\r<BR>\n" );
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document.write( "So you need 14  5/8 lots, but you can only have a whole number of lots. So round down to get the final answer of <font color=\"red\">14 lots</font>. </SPAN>\n" );
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