document.write( "Question 55605This question is from textbook algebra 1
\n" ); document.write( ": twice the greater of two consecutive odd integers is 13 less than three times the lesser. find the number\r
\n" ); document.write( "\n" ); document.write( "define a variable
\n" ); document.write( "write equation
\n" ); document.write( "solve\r
\n" ); document.write( "\n" ); document.write( "can you show me how to do this problem please?
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Algebra.Com's Answer #37743 by pwac(253)\"\" \"About 
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Let x = smaller number,
\n" ); document.write( "so x + 2 will be greater number.
\n" ); document.write( "We need to devise an equation now.
\n" ); document.write( "Three times the smaller number will be 3x
\n" ); document.write( "This is 13 less than twice the greater 2(x+2)
\n" ); document.write( "so the equation will look like this:
\n" ); document.write( "3x - 13 = 2(x+2). Multiply out right hand side to get
\n" ); document.write( "3x-13 = 2x+4 Subtract 2x from both sides
\n" ); document.write( "3x-2x-13 = 4
\n" ); document.write( "x-13 = 4 Add 13 to both sides
\n" ); document.write( "x = 4+13
\n" ); document.write( "x=17 This is the smaller number
\n" ); document.write( "so greater number is x+2 =19
\n" ); document.write( "Answer is 17 and 19
\n" ); document.write( "Pete
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