document.write( "Question 55605This question is from textbook algebra 1
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document.write( ": twice the greater of two consecutive odd integers is 13 less than three times the lesser. find the number\r
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document.write( "define a variable
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document.write( "write equation
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document.write( "solve\r
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document.write( "can you show me how to do this problem please? \n" );
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Algebra.Com's Answer #37743 by pwac(253)![]() ![]() ![]() You can put this solution on YOUR website! Let x = smaller number, \n" ); document.write( "so x + 2 will be greater number. \n" ); document.write( "We need to devise an equation now. \n" ); document.write( "Three times the smaller number will be 3x \n" ); document.write( "This is 13 less than twice the greater 2(x+2) \n" ); document.write( "so the equation will look like this: \n" ); document.write( "3x - 13 = 2(x+2). Multiply out right hand side to get \n" ); document.write( "3x-13 = 2x+4 Subtract 2x from both sides \n" ); document.write( "3x-2x-13 = 4 \n" ); document.write( "x-13 = 4 Add 13 to both sides \n" ); document.write( "x = 4+13 \n" ); document.write( "x=17 This is the smaller number \n" ); document.write( "so greater number is x+2 =19 \n" ); document.write( "Answer is 17 and 19 \n" ); document.write( "Pete \n" ); document.write( " |