document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=595931>Question 595931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me whith geometric problem thanks in the below point A is 8ft away from a circle of Radius =5ft line AB is tangential to the circle what is the distrance AB? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #377413 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=377413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Solution depends upon the assumption that B is the point of tangency of the line containing the segement AB.\r<BR>\n" );
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document.write( "Label the center of the circle as point O.  Construct the radius OB and the segment OA.  A radius to a point of tangency is perpendicular to the tangent line, hence triangle AOB is a right triangle.\r<BR>\n" );
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document.write( "Label the point of intersection of the circle and the line segment OA as point D.  Note that OD is a radius so OD measures 5 ft.  Note that DA is given as 8 ft.  Finally, the measure of OA is the sum of the measures of OD and DA, which is to say 13 feet.\r<BR>\n" );
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document.write( "Note that OB is a radius and therefore measures 5 ft.\r<BR>\n" );
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document.write( "Note that you have a right triangle where the short leg measures 5 ft and the hypotenuse measures 13 ft.\r<BR>\n" );
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document.write( "Use the Pythagorean Theorem to calculate the measure of the other leg of the triangle, namely the segment AB.\r<BR>\n" );
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document.write( "Quick method:  Recall the Pythagorean triple where 5 is the smallest value and 13 is the largest value.  Use the third value as the measure of AB.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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