document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=595841>Question 595841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me step by step on how to solve: -2log base 4(x)= log base 4(3)^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #377372 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=377372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Can you help me step by step on how to solve:<BR>\n" );
document.write( "-2log base 4(x)= log base 4(3)^2<BR>\n" );
document.write( "log base 4(3)^2+2log base 4(x)=0<BR>\n" );
document.write( "log base 4(9)+log base 4(x^2)=0<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log4[9*x^2]=0<BR>\n" );
document.write( "convert to exponential form: base(4) raised to log of number(0)=number(9x^2)<BR>\n" );
document.write( "4^0=9x^2=1<BR>\n" );
document.write( "x^2=1/9<BR>\n" );
document.write( "x=-1/3(reject, x>0)<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x=1/3 </SPAN>\n" );
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