document.write( "Question 595883: Solve simultaneously I dont understand..\\r
\n" ); document.write( "\n" ); document.write( "y=x^2-4x-2
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Algebra.Com's Answer #377358 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If y=x^2-4x-2 and y = x-2, then we can say \r
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\n" ); document.write( "\n" ); document.write( "x - 2 = x^2-4x-2\r
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\n" ); document.write( "\n" ); document.write( "This is because the two are both simultaneously equal to y. So they must be equal to each other.\r
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\n" ); document.write( "\n" ); document.write( "From here, solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+-+2+=+x%5E2-4x-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"0+=+x%5E2-4x-2+-+x+%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "\"0+=+x%5E2-5x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-5x+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-5%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\" or \"x-5+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\" or \"x=5\"\r
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\n" ); document.write( "\n" ); document.write( "If x = 0, then y = x-2 = 0-2 = -2\r
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\n" ); document.write( "\n" ); document.write( "So if x = 0 then y = -2\r
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\n" ); document.write( "\n" ); document.write( "So one ordered pair solution is (0, -2)\r
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\n" ); document.write( "\n" ); document.write( "If x = 5, then y = x-2 = 5-2 = 3\r
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\n" ); document.write( "\n" ); document.write( "So when x = 5, the value of y is y = 3\r
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\n" ); document.write( "\n" ); document.write( "So another ordered pair solution is (5, 3)
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