document.write( "Question 595821: How would I find an equation of the line throught (2,2) that is parallel to the line passing through (4,5) and (10,-2)? \n" ); document.write( "
Algebra.Com's Answer #377330 by mananth(16946)\"\" \"About 
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x1 y1 x2 y2
\n" ); document.write( "4 5 10 -2
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\n" ); document.write( "slope m = (y2-y1)/(x2-x1)
\n" ); document.write( "( -2 - 5 )/( 10 - 4 )
\n" ); document.write( "( -7 / 6 )
\n" ); document.write( "m= -7/6 \r
\n" ); document.write( "\n" ); document.write( "The equation of line parallel to the line passing through the above points will be the same = -7/6
\n" ); document.write( "m= -1 1/ 6
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\n" ); document.write( "Plug value of the slope and point(2,2)
\n" ); document.write( "y=mx+b
\n" ); document.write( "2.00 = -7/6 * 2 +b
\n" ); document.write( "b= 2 + 7/3
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\n" ); document.write( "b= 13/ 3
\n" ); document.write( "So the equation will be
\n" ); document.write( "Y = (-7/6) x + 13/3
\n" ); document.write( "m.ananth@hotmail.ca
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