document.write( "Question 595725: Today Janet's age in years is three times her dog's age ing months, In one year, the dog's age in months will be 2 times Janet's age then, in years. Today Janet is _________ years old. Please show your work. \n" ); document.write( "
Algebra.Com's Answer #377282 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Today Janet's age in years is three times her dog's age in months,
\n" ); document.write( " In one year, the dog's age in months will be 2 times Janet's age then, in years.
\n" ); document.write( ":
\n" ); document.write( "Let j = Janet's age in years
\n" ); document.write( "Let d = dog's age in months
\n" ); document.write( ":
\n" ); document.write( "\"Janet's age in years is three times her dog's age in months,\"
\n" ); document.write( "j = 3d
\n" ); document.write( ":
\n" ); document.write( "\"In one year, the dog's age in months will be 2 times Janet's age then, in years.\"
\n" ); document.write( "d + 12 = 2(j+1)
\n" ); document.write( "d + 12 = 2j + 2
\n" ); document.write( "d = 2j + 2 - 12
\n" ); document.write( "d = 2j - 10
\n" ); document.write( "replace j with 3d
\n" ); document.write( "d = 2(3d) - 10
\n" ); document.write( "10 = 6d - d
\n" ); document.write( "10 = 5d
\n" ); document.write( "d = 10/5
\n" ); document.write( "d = 2 months is the dogs age
\n" ); document.write( "then
\n" ); document.write( "j = 3(2)
\n" ); document.write( "j = 6 yrs is Janet's age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this in the statement:
\n" ); document.write( "\"In one year, the dog's age in months will be 2 times Janet's age then, in years.
\n" ); document.write( "2 + 12 = 2(6+1)
\n" ); document.write( "14 = 2(7)
\n" ); document.write( " \n" ); document.write( "
\n" );