document.write( "Question 595628: A ball is thrown straight upward with an initial velocity of 52 ft/sec. Its height above the ground after seconds is given by the formula h(t)=-16t^2+52t. Whta is the maximum height that the ball attains before hitting the ground (feet)? \n" ); document.write( "
| Algebra.Com's Answer #377221 by nerdybill(7384)     You can put this solution on YOUR website! A ball is thrown straight upward with an initial velocity of 52 ft/sec. Its height above the ground after seconds is given by the formula h(t)=-16t^2+52t. What is the maximum height that the ball attains before hitting the ground (feet)? \n" ); document.write( ". \n" ); document.write( "Max height is at the vertex. \n" ); document.write( "Value of t at vertex is: \n" ); document.write( "t = -b/(2a) \n" ); document.write( "t = -52/(2(-16)) \n" ); document.write( "t = -52/(-32) \n" ); document.write( "t = 1.625 \n" ); document.write( ". \n" ); document.write( "Height at this time is: \n" ); document.write( "h(t)=-16t^2+52t \n" ); document.write( "h(1.625)=-16(1.625)^2+52(1.625) \n" ); document.write( "h(1.625)= 42.25 feet\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |