document.write( "Question 595628: A ball is thrown straight upward with an initial velocity of 52 ft/sec. Its height above the ground after seconds is given by the formula h(t)=-16t^2+52t. Whta is the maximum height that the ball attains before hitting the ground (feet)? \n" ); document.write( "
Algebra.Com's Answer #377221 by nerdybill(7384)\"\" \"About 
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A ball is thrown straight upward with an initial velocity of 52 ft/sec. Its height above the ground after seconds is given by the formula h(t)=-16t^2+52t. What is the maximum height that the ball attains before hitting the ground (feet)?
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\n" ); document.write( "Max height is at the vertex.
\n" ); document.write( "Value of t at vertex is:
\n" ); document.write( "t = -b/(2a)
\n" ); document.write( "t = -52/(2(-16))
\n" ); document.write( "t = -52/(-32)
\n" ); document.write( "t = 1.625
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\n" ); document.write( "Height at this time is:
\n" ); document.write( "h(t)=-16t^2+52t
\n" ); document.write( "h(1.625)=-16(1.625)^2+52(1.625)
\n" ); document.write( "h(1.625)= 42.25 feet\r
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