document.write( "Question 595489: if secx=4 what does cos2x= \n" ); document.write( "
Algebra.Com's Answer #377179 by jim_thompson5910(35256)\"\" \"About 
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sec(x) = 4\r
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\n" ); document.write( "\n" ); document.write( "1/cos(x) = 4\r
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\n" ); document.write( "\n" ); document.write( "1 = 4*cos(x)\r
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\n" ); document.write( "\n" ); document.write( "1/4 = cos(x) \r
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\n" ); document.write( "\n" ); document.write( "cos(x) = 1/4\r
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\n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r
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\n" ); document.write( "\n" ); document.write( "cos(2x)\r
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\n" ); document.write( "\n" ); document.write( "2*(cos(x))^2 - 1\r
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\n" ); document.write( "\n" ); document.write( "2*(1/4)^2 - 1\r
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\n" ); document.write( "\n" ); document.write( "2*(1/16) - 1\r
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\n" ); document.write( "\n" ); document.write( "1/8 - 1\r
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\n" ); document.write( "\n" ); document.write( "-7/8\r
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\n" ); document.write( "\n" ); document.write( "So if sec(x) = 4, then cos(2x) = -7/8
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