document.write( "Question 595498: If sin t= 5/13, what is cos t? \n" ); document.write( "
Algebra.Com's Answer #377177 by jim_thompson5910(35256)\"\" \"About 
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sin^2 + cos^2 = 1\r
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\n" ); document.write( "\n" ); document.write( "(5/13)^2 + cos^2 = 1\r
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\n" ); document.write( "\n" ); document.write( "25/169 + cos^2 = 1\r
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\n" ); document.write( "\n" ); document.write( "cos^2 = 1 - 25/169\r
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\n" ); document.write( "\n" ); document.write( "cos^2 = 144/169\r
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\n" ); document.write( "\n" ); document.write( "cos = sqrt(144/169)\r
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\n" ); document.write( "\n" ); document.write( "cos = 12/13\r
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\n" ); document.write( "\n" ); document.write( "So cos(t) = 12/13
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