document.write( "Question 595498: If sin t= 5/13, what is cos t? \n" ); document.write( "
Algebra.Com's Answer #377177 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! sin^2 + cos^2 = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(5/13)^2 + cos^2 = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "25/169 + cos^2 = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cos^2 = 1 - 25/169\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cos^2 = 144/169\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cos = sqrt(144/169)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cos = 12/13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So cos(t) = 12/13 \n" ); document.write( " |