document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=595463>Question 595463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 9x+8y=-37<BR>\n" );
document.write( "x=-2-3y\r<BR>\n" );
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document.write( "solve by substitution method </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #377149 by </B><A HREF=/tutors/aboutme.mpl?userid=shellyhotgirl><B>shellyhotgirl(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shellyhotgirl><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=377149\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9x+8y=-37<BR>\n" );
document.write( "x=-2-3y\r<BR>\n" );
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document.write( "solve by substitution method\r<BR>\n" );
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document.write( "use the first equation 9x+8y=-37 and substiute x in this equation with the second one\r<BR>\n" );
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document.write( "9(-2-3y)+8y=-37<BR>\n" );
document.write( "-18-27y+8y=-37   multiply by 9<BR>\n" );
document.write( "-27y+8y=-19      add 18 to each side<BR>\n" );
document.write( "-19y=-19         add like terms and then divde to get y by itself<BR>\n" );
document.write( "y=1\r<BR>\n" );
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document.write( "Now that you have y=1 plug it into the second equation to find what x is look something like\r<BR>\n" );
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document.write( "x=-2-3(1) </SPAN>\n" );
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