document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=595338>Question 595338</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I have a triangle, and one side is 35 degrees, and the other side is 28 degrees, how do I figure out the last side? I know you have to add them together and then you have to subtract, but I don't know what you subtract by. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #377088 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=377088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If I have a triangle, and one side is 35 degrees, and the other side is 28 degrees, how do I figure out the last side? I know you have to add them together and then you have to subtract, but I don't know what you subtract by.<BR>\n" );
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document.write( "Sides are units of length, not degrees.  Unless you mean a spherical triangle, which I doubt.<BR>\n" );
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document.write( "Assuming you mean the angles, the sum is always 180 degs.<BR>\n" );
document.write( "35 + 28 = 63 degs<BR>\n" );
document.write( "The 3rd angle is 180 - 63 degs<BR>\n" );
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