document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=595232>Question 595232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the logrithmic equation.  Round answers to 2 decimal places when necessary.\r<BR>\n" );
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document.write( "log 6x  -  3  =  - 4<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #377041 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=377041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(6x  -  3)  =  - 4\r<BR>\n" );
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document.write( "6x  -  3  =  10^(-4)\r<BR>\n" );
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document.write( "6x  -  3  =  0.0001\r<BR>\n" );
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document.write( "6x  =  0.0001+3\r<BR>\n" );
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document.write( "6x  =  3.0001\r<BR>\n" );
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document.write( "x  =  3.0001/6\r<BR>\n" );
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document.write( "x  =  0.5000167\r<BR>\n" );
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document.write( "So the solution is approximately x  =  0.5000167\r<BR>\n" );
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document.write( "Rounded to two decimal places, the solution is x = 0.50 </SPAN>\n" );
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