document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=595084>Question 595084</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 4 centimeters less than twice its width. the perimeter of the rectangle is 64cm. what are the dimensions of the rectangle? Having trouble figuring out this one. Thanks<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376998 by </B><A HREF=/tutors/aboutme.mpl?userid=llorton><B>llorton(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=llorton><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l = length of rectangle in centimeters<BR>\n" );
document.write( "w = width of rectangle in centimeters\r<BR>\n" );
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document.write( "l = 2*w - 4   (The length is 4 cm less than twice its width.)<BR>\n" );
document.write( "2*l + 2*w = 64  (The perimeter equals 64 cm. = 2*length + 2*width)\r<BR>\n" );
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document.write( "2*(2*w-4) + 2*w = 64<BR>\n" );
document.write( "4*w - 8 + 2*w = 64<BR>\n" );
document.write( "6*w -8 = 64<BR>\n" );
document.write( "6*w - 8 + 8 = 64 + 8<BR>\n" );
document.write( "6*w = 72<BR>\n" );
document.write( "6*w/6 = 72/6<BR>\n" );
document.write( "w = 12<BR>\n" );
document.write( "l = 2*12 - 4 = 24 - 4 = 20\r<BR>\n" );
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document.write( "check: 2*12 + 2*20 = 24 + 40 = 64\r<BR>\n" );
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document.write( "The answers are length = 20 cm. and width = 12 cm.\r<BR>\n" );
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