document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=594954>Question 594954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve for the dimensions of a rectangle given it's area of 160 and it is incribed in a circle with a diameter of 20 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376977 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> so the diagonal is 20\r<BR>\n" );
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document.write( "L * W = 160 (area equation)\r<BR>\n" );
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document.write( "L^2 + W^2 = 20^2 (Pythagoras)\r<BR>\n" );
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document.write( "2LW = 320\r<BR>\n" );
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document.write( "L^2 + 2LW + W^2 = 20^2 + 320 ___ (L + W)^2 = 4320 ___ L + W = 12&#8730;30\r<BR>\n" );
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document.write( "L^2 - 2LW + W^2 = 20^2 - 320 ___ (L - W)^2 = 3680 ___ L - W = 4&#8730;230 </SPAN>\n" );
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