document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=594914>Question 594914</A>: <I><SPAN STYLE=\"word-break: break-all;\"> we have atriangle ABC. Measure of angle A is 105 deg.  Length of Side B is equal root2*SideC.   then what is the measure of angle C?\r<BR>\n" );
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document.write( "i know the answer. i need solution with basic geometry.  without trigonometry.\r<BR>\n" );
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document.write( "thanks already. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376972 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sizes of angles and their relationships to the lengths of the opposite sides, unfortunately involves trig<BR>\n" );
document.write( "___ the Law of Sines states that the lengths of the sides is in the same proportion as the sines of the opposite angles\r<BR>\n" );
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document.write( "since A is 105º, B plus C is 75º - like 30º plus 45º\r<BR>\n" );
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document.write( "sin(30º) = 1/2 ___ sin(45º) = &#8730;2 / 2\r<BR>\n" );
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document.write( "looks like angle C is 30º </SPAN>\n" );
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