document.write( "Question 55555: x+152=28 \n" ); document.write( "

Algebra.Com's Answer #37697 by tutorcecilia(2152) $\"\"$ $\"About$

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x+152=28
\n" ); document.write( "x+152-152=28-152
\n" ); document.write( "x=-124
\n" ); document.write( ".
\n" ); document.write( "Check by plugging (x=-124) back into the original equation:
\n" ); document.write( "x+152=28
\n" ); document.write( "(-124)+152=28
\n" ); document.write( "28=28 \n" ); document.write( "

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