document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=594781>Question 594781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Side A of a triangle is twice side B. Side C is 2m shorter than side A. The perimeter is 98m. Find the length of each side. \r<BR>\n" );
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document.write( "This is what is was working on, but at the end, when I added up the sides, they did not equal 98m.\r<BR>\n" );
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document.write( "A + B + C = Perimeter                           <BR>\n" );
document.write( "A= 2B, B= B, C= A-2 or 2B - 2<BR>\n" );
document.write( "2B + B + 2B - 2 = 98<BR>\n" );
document.write( "5B = 100<BR>\n" );
document.write( "B = 25m\r<BR>\n" );
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document.write( "Therefore, 98 = 50 + 25 + 48, but it doesn't<BR>\n" );
document.write( "                A    B    C<BR>\n" );
document.write( "Can you explain, please?<BR>\n" );
document.write( "                A    B    C </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376903 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> oops...arithmetic\r<BR>\n" );
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document.write( "5B = 100 ___ B = 20 </SPAN>\n" );
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