document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=594671>Question 594671</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the remaining zeros of of f(x) given that c is a zero. Then re-write f(x) in a completely factored form.<BR>\n" );
document.write( "f(x)=2x^3+15x^2+22x-15; c=1/2 is a zero.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376865 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376865\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the remaining zeros of of f(x) given that c is a zero. Then re-write f(x) in a completely factored form. f(x)=2x^3+15x^2+22x-15; c=1/2 is a zero.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "dividing by synthetic division:\r<BR>\n" );
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document.write( "...1/2...|.....2......15......22.......-15.............<BR>\n" );
document.write( "...........................1........8.........15......<BR>\n" );
document.write( ".................2......16......30.........0....<BR>\n" );
document.write( "f(x)=(2x-1)(2x^2+16x+30)<BR>\n" );
document.write( "f(x)=(2x-1)(2x+10)(x+3) </SPAN>\n" );
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