document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=594526>Question 594526</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve: 3n(n-2)!/(n-3)=105 Solve for \"n\" State any restrictions.\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376855 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{3n(n-2)!}{n-3} = 105\">, Divide through by 3\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{n(n-2)!}{n-3} = 35\">\r<BR>\n" );
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document.write( "We can write n(n-2)! as n!/(n-1). Above equation is equivalent to\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{n!}{(n-1)(n-3)} = 35\"> or <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE n(n-2)(n-4)! = 35\">\r<BR>\n" );
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document.write( "Here it is obvious that n should be fairly small (at most 8 because (8-4)! = 24). However, n must be at least 7 (because n(n-2)(n-4)! &#8801; 0 (mod 7)). Therefore there are no solutions. </SPAN>\n" );
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