document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=594573>Question 594573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 3% acid solution must be mixed with 60 gallons of 10% acid solution to make an acid solution that is 8%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376805 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -------------- 	percent	----------------	Amount								<BR>\n" );
document.write( "Acid solution	60	----------------			10	gallons					<BR>\n" );
document.write( "Acid solution type II	3	----------------			x	gallons					<BR>\n" );
document.write( "Mixture	8	----------------	10	+	x	gallons					<BR>\n" );
document.write( "											<BR>\n" );
document.write( "60*10+3x=8(10+x)<BR>\n" );
document.write( "600+3x	=80+8x			<BR>\n" );
document.write( "3x-8x=-600+80			<BR>\n" );
document.write( "-5x=-520								<BR>\n" );
document.write( "/	-5										<BR>\n" );
document.write( "x=104		gallons	Acid solution type II						<BR>\n" );
document.write( "											<BR>\n" );
document.write( "m.ananth@hotmail.ca											<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );