document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=594389>Question 594389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello my Question is: In a 30-60-90 triangle if the shorter leg has length P then what is the length of the longer leg and what would  length of the hypotenuse be.<BR>\n" );
document.write( "Please help me :( I really dont understand this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376722 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376722\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> picture an equilateral triangle (60-60-60)\r<BR>\n" );
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document.write( "a perpendicular bisector of the base divides the equilateral into two 30-60-90 triangles\r<BR>\n" );
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document.write( "if the shorter side (half the base) is P, then the hypotenuse (one of the other equilateral sides) is 2P\r<BR>\n" );
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document.write( "using Pythagoras to find the longer leg ___ P^2 + x^2 = (2P)^2 ___ x^2 = 3P^2 ___ x = P&#8730;3 </SPAN>\n" );
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