document.write( "Question 593945: 5x^2+5y^2-20=0 in standard form \n" ); document.write( "

Algebra.Com's Answer #376697 by lwsshak3(11628) $\"\"$ $\"About$

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5x^2+5y^2-20=0 in standard form
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\n" ); document.write( "5x^2+5y^2-20=0
\n" ); document.write( "divide by 5
\n" ); document.write( "5x^2+5y^2-20=0
\n" ); document.write( "x^2+y^2-4=0
\n" ); document.write( "x^2+y^2=4
\n" ); document.write( "This is an equation of a circle with center at (0,0) and radius=2, of the standard form:
\n" ); document.write( "(x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center and r=radius
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