document.write( "Question 594112: Write an equation for the conic section:
\n" ); document.write( "A hyperbola with foci at (-3,0) and (3,0) and vertices at (2,0) and (-2,0).
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Algebra.Com's Answer #376696 by lwsshak3(11628)\"\" \"About 
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Write an equation for the conic section:
\n" ); document.write( "A hyperbola with foci at (-3,0) and (3,0) and vertices at (2,0) and (-2,0).
\n" ); document.write( "**
\n" ); document.write( "Equation is that for a hyperbola with horizontal transverse axis of the standard form:
\n" ); document.write( "(x-h)^2/a^2-(y-k)^2/b^2=1,(h,k)=(x,y) coordinates of center.
\n" ); document.write( "For given hyperbola:
\n" ); document.write( "center: (0,0)
\n" ); document.write( "length of horizontal transverse axis=4 (-2 to 2)=2a
\n" ); document.write( "a=2
\n" ); document.write( "a^2=4
\n" ); document.write( "..
\n" ); document.write( "2c=6 (-3 to 3)
\n" ); document.write( "c=3
\n" ); document.write( "c^2=9
\n" ); document.write( "..
\n" ); document.write( "c^2=a^2+b^2
\n" ); document.write( "b^2=c^2-a^2=9-4=5
\n" ); document.write( "..
\n" ); document.write( "Equation:
\n" ); document.write( "x^2/4-y^2/5=1
\n" ); document.write( "
\n" );