document.write( "Question 594211: 36x^2+9y^2+72x-18y-279
\n" ); document.write( "how to get standard form \n" ); document.write( "

Algebra.Com's Answer #376695 by lwsshak3(11628) $\"\"$ $\"About$

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36x^2+9y^2+72x-18y-279
\n" ); document.write( "how to get standard form
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\n" ); document.write( "Standard form is an equation, so I assume you forgot to make given expression=0
\n" ); document.write( "36x^2+9y^2+72x-18y-279=0
\n" ); document.write( "complete the square
\n" ); document.write( "36(x^2+2x+1)+9(y^2-2y+1)=279+36+9
\n" ); document.write( "36(x+1)^2+9(y-1)^2=324
\n" ); document.write( "divide by 324
\n" ); document.write( "(x+1)^2/9+(y-1)^2/36=1
\n" ); document.write( "This is an equation of an ellipse with vertical major axis with center at (-1,1).
\n" ); document.write( "Its standard form: (x-h)^2/b^2+(y-k)^2/a^2=1, a>b, (h,k)=(x,y) coordinates of center.
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