document.write( "Question 594224: There are eleven players on the basketball team. How many ways can a starting lineup of five players be chosen?\r
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document.write( "I did 11x5 and got 55 but I dont think that is right. \n" );
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Algebra.Com's Answer #376655 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! There are eleven players on the basketball team. How many ways can a starting lineup of five players be chosen? \n" ); document.write( "I did 11x5 and got 55 but I dont think that is right. \n" ); document.write( "-------------------- \n" ); document.write( "Ans: 11C5 = 11!/(6!*5!) = (11*10*9*8*7)/(1*2*3*4*5) = 462 ways \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |