document.write( "Question 594224: There are eleven players on the basketball team. How many ways can a starting lineup of five players be chosen?\r
\n" ); document.write( "\n" ); document.write( "I did 11x5 and got 55 but I dont think that is right.
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Algebra.Com's Answer #376655 by stanbon(75887)\"\" \"About 
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There are eleven players on the basketball team. How many ways can a starting lineup of five players be chosen?
\n" ); document.write( "I did 11x5 and got 55 but I dont think that is right.
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\n" ); document.write( "Ans: 11C5 = 11!/(6!*5!) = (11*10*9*8*7)/(1*2*3*4*5) = 462 ways
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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