document.write( "Question 593530: Factor By Grouping:\r
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Algebra.Com's Answer #376614 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"4x%5E3-6x%5E2%2B10x-15\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%284x%5E3-6x%5E2%29%2B%2810x-15%29\" Group the terms in two pairs\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%282x-3%29%2B5%282x-3%29\" Factor out the GCF \"2x%5E2\" out of the first group. Factor out the GCF \"5\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%5E2%2B5%29%282x-3%29\" Since we have the common term \"2x-3\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"4x%5E3-6x%5E2%2B10x-15\" factors to \"%282x%5E2%2B5%29%282x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"4x%5E3-6x%5E2%2B10x-15=%282x%5E2%2B5%29%282x-3%29\" for all values of x
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