document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=594093>Question 594093</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jessica is older than Janet. Their sum of their ages is 38 years. Twice janets age plus jessicas age is 51. How old is janet?\r<BR>\n" );
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document.write( "I tried:<BR>\n" );
document.write( "Let x be greater <BR>\n" );
document.write( "x=Jessica <BR>\n" );
document.write( "y = Janet\r<BR>\n" );
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document.write( "x+ y = 38\r<BR>\n" );
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document.write( "2y+x=51\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376600 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have the correct equations. Now you just need to solve.\r<BR>\n" );
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document.write( "x+ y = 38\r<BR>\n" );
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document.write( "y = 38-x\r<BR>\n" );
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document.write( "2y+x=51 \r<BR>\n" );
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document.write( "2(38-x)+x=51 \r<BR>\n" );
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document.write( "Here you now have an equation with one variable. I'll let you solve it.\r<BR>\n" );
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document.write( "Once you find the value of x, use it with y = 38-x to find the value of y. </SPAN>\n" );
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