document.write( "Question 6843: I would appreciate it if a tutor could verify my answer to the below question.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve for x: sqrt(5-x) +3=sqrt(3x+4)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "My answer:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "sqrt(3x+4)^2=[(sqrt(5-x)+3]^2
\n" ); document.write( "3x+4=(5-x)+(6)sqrt(5-x)+9
\n" ); document.write( "3x+4=14-x+(6)sqrt(5-x)
\n" ); document.write( "4x-10=(6)sqrt(5-x)
\n" ); document.write( "(4x-10)^2=[(6)sqrt(5-x)]^2
\n" ); document.write( "16x^2-80x+100=36(5-x)
\n" ); document.write( "16x^2-80x+100=180-36x
\n" ); document.write( "16x^2-44x-80=0
\n" ); document.write( "(16x+20)(x-4)
\n" ); document.write( "16x+20=0 or x-4=0
\n" ); document.write( "16x/16=20/16 or x=4
\n" ); document.write( "x=-5/4 or x=4
\n" ); document.write( "****x=-5/4 is an extraneous solution****\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In advance, thank you for your assistance! \n" ); document.write( "
Algebra.Com's Answer #3766 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
you are correct, but the -5/4 value is a valid answer..if you know Complex numbers. If not, then you can indeed ignore this answer.\r
\n" ); document.write( "\n" ); document.write( "Well done.
\n" ); document.write( "Jon.
\n" ); document.write( " \n" ); document.write( "
\n" );