document.write( "Question 593989: The L.C.M of two numbers is 120 and their G.C.F is 6. one of the numbers is 30, what is the other number?
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Algebra.Com's Answer #376592 by Edwin McCravy(20086)\"\" \"About 
You can put this solution on YOUR website!
The L.C.M of two numbers is 120 and their G.C.F is 6. one of the numbers is 30, what is the other number?
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document.write( "Easy way:\r\n" );
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document.write( "The product of the GCF and the LCM of two numbers is the product of the two numbers\r\n" );
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document.write( "Let the other number be N.\r\n" );
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document.write( "Then GCF×LCM = 30N or\r\n" );
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document.write( "      6(120) = 30N\r\n" );
document.write( "         720 = 30N\r\n" );
document.write( "          24 = N\r\n" );
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document.write( "HARDER WAY but involves thinking not a memorized formula:\r\n" );
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document.write( " 30 = 2    ×3×5\r\n" );
document.write( "  ? = ?  \r\n" );
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document.write( "      2    ×3   = 6\r\n" );
document.write( "      2×2×2×3×5 = 120\r\n" );
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document.write( "Rule for L.C.M\r\n" );
document.write( "The L.C.M. of two positive integers must have a prime factor \r\n" );
document.write( "the MOST number of times which ONE of them has it as a factor. \r\n" );
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document.write( "Ruke for G.C.F\r\n" );
document.write( "The G.C.F. of two positive integers must have a prime factor \r\n" );
document.write( "the LEAST number of times which BOTH of them have it as a factor.\r\n" );
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document.write( "L.C.M. = 120 has 2 as a factor three times, so the MOST number \r\n" );
document.write( "of times 30 or the other number has it as a factor is three times.\r\n" );
document.write( "30 only has 2 as a factor 1 time, so the other number must have 2\r\n" );
document.write( "as a factor 3 times.  So the other number is at least 2×2×2\r\n" );
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document.write( "G.C.F. = 6 has 2 and 3 once each as its prime factors.  30 has both these\r\n" );
document.write( "factors once so the other number must have both of them once, so the other\r\n" );
document.write( "number must have factor 2 and 3.\r\n" );
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document.write( "We have already determined that it must have 2 as a factor, (in fact it\r\n" );
document.write( "must have it three times); therefore the other number has 2 as a factor \r\n" );
document.write( "3 times and 3 as a factor once.\r\n" );
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document.write( "So the other number is 2×2×2×3 = 24.\r\n" );
document.write( "Infact you can fill it in from this chart:\r\n" );
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document.write( " 30 = 2    ×3×5\r\n" );
document.write( "  ? = ?  \r\n" );
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document.write( "      2    ×3   = 6\r\n" );
document.write( "      2×2×2×3×5 = 120\r\n" );
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document.write( "Bring up the factor not represented by one of the numbers \r\n" );
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document.write( " 30 = 2    ×3×5\r\n" );
document.write( " 24 = 2×2×2×3  \r\n" );
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document.write( "      2    ×3   = 6\r\n" );
document.write( "      2×2×2×3×5 = 120\r\n" );
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document.write( "Edwin
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