document.write( "Question 55496: The sum of three consecutive integers is 42\r
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Algebra.Com's Answer #37657 by funmath(2933)\"\" \"About 
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The sum of three consecutive integers is 42\r
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\n" ); document.write( "When we count we are counting by adding 1's:
\n" ); document.write( "1,1+1,1+1+1,1+1+1+1,...=1,2,3,4,...
\n" ); document.write( "Therefore,
\n" ); document.write( "Let the 1st integer be:x
\n" ); document.write( "Then the 2nd integer is: x+1
\n" ); document.write( "Then the thrid integer is: x+1+1=x+2
\n" ); document.write( "Sum means add:
\n" ); document.write( "(x)+(x+1)+(x+2)=42
\n" ); document.write( "x+x+1+x+2=42
\n" ); document.write( "3x+3=42
\n" ); document.write( "3x+3-3=42-3
\n" ); document.write( "3x=39
\n" ); document.write( "3x/3=39/3
\n" ); document.write( "x=13
\n" ); document.write( "The 1st integer is:x=13
\n" ); document.write( "The 2nd integer is:x+1=13+1=14
\n" ); document.write( "The 3rd integer is: x+2=13+2=15
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\n" ); document.write( "Check, does 13+14+15=42?
\n" ); document.write( "Yes, we're right!!!
\n" ); document.write( "Happy Calculating!!!
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