document.write( "Question 593699: State the amplitude, period, phase shift, and vertical shift for Y=2 cos 1/2( theta + pi/2 ) -2 Then graph the function. \n" ); document.write( "
Algebra.Com's Answer #376554 by lwsshak3(11628)\"\" \"About 
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State the amplitude, period, phase shift, and vertical shift for Y=2 cos 1/2( theta + pi/2 ) -2 Then graph the function.
\n" ); document.write( "**
\n" ); document.write( "Use x for theta
\n" ); document.write( "Equation for graphing cos functions: y=Acos(Bx-C), A=amplitude,Period=2π/B, Phase shift=C/B
\n" ); document.write( "For given equation:
\n" ); document.write( "2cos(1/2)(x+π/2)-2:
\n" ); document.write( "re-write equation:
\n" ); document.write( "2cos(x/2+π/4)-2
\n" ); document.write( "Amplitude=2
\n" ); document.write( "B=1/2
\n" ); document.write( "period=2π/B=2π/(1/2)=4π
\n" ); document.write( "1/4 period=π
\n" ); document.write( "C=π/4
\n" ); document.write( "phase shift=C/B=(π/4)/(1/2)=π/2 (to the left)
\n" ); document.write( "curve is bumped down 2 units.
\n" ); document.write( "..
\n" ); document.write( "Drawing a graph for one period with x-axis scale in radians:
\n" ); document.write( "With no phase-shift, coordinates of given cos function are as follows:
\n" ); document.write( "(0,2), (π,0), (2π,-2), (3π,0), (4π,2)
\n" ); document.write( "..
\n" ); document.write( "With phase-shift to the left, x-coordinates are changed as follows:
\n" ); document.write( "(-π/2,2), (π/2,0), (3π/2,-2), (5π/2,0), (7π/2,2)
\n" ); document.write( "..
\n" ); document.write( "With bumping of 2 units down, y-coordinates are changed as follows:
\n" ); document.write( "(-π/2,0), (π/2,-2), (3π/2,-4), (5π/2,-2), (7π/2,0)
\n" ); document.write( "These are coordinates of the final curve you can graph.\r
\n" ); document.write( "\n" ); document.write( "One more item to calculate:
\n" ); document.write( "y-intercept
\n" ); document.write( "x=0
\n" ); document.write( "2cos(x/2+π/4)-2
\n" ); document.write( "2cos(π/4)-2
\n" ); document.write( "2*√2/2-2=√2-2≈-.59\r
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