document.write( "Question 593904: I am having trouble with the setup this question.
\n" ); document.write( "A food server examines the amount of money earned in tips after working an 8-hour shift. The server has a total of $191 in denominations of $1, $5, $10, and $20 bills. The total number of paper bills is 53. The number of $5 bills is 4 times the number of $10 bills, and the number of $1 bills is 1 less than twice the number of $5 bills. Write a system of linear equations to represent the situation. Then use matrices to find the number of each denomination.\r
\n" ); document.write( "\n" ); document.write( "I have set up for the equations, where a =$1 bills, b=$5 bills, c=$10 bills and d=$20 bills
\n" ); document.write( "a + b + c + d =53
\n" ); document.write( "a + 5b +10c +20d =191
\n" ); document.write( "0 + b - 4c + 0 = 0 from the relationship b=4c
\n" ); document.write( "a - 2b + 0 + 0 = -1 from the relationship a=2b-1\r
\n" ); document.write( "\n" ); document.write( "I have tried solving it a couple of different ways, and I keep getting to a point that it doesn’t work. Do I have this set up correctly or am I missing something?
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #376543 by AnlytcPhil(1810)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "You have it set up correctly and the solution is\r\n" );
document.write( "\r\n" );
document.write( "a = 31 ones\r\n" );
document.write( "b = 16 fives\r\n" );
document.write( "c = 4 tens\r\n" );
document.write( "d = 2 twenties.\r\n" );
document.write( "\r\n" );
document.write( "Keep working it.  You're bound to get it if you don't\r\n" );
document.write( "make a mistake.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );