document.write( "Question 593861: (3a^2+7a-20)/(a+4) \n" ); document.write( "

Algebra.Com's Answer #376498 by Eva18(13) $\"\"$ $\"About$

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(3a^2+7a-20)/(a-4):
\n" ); document.write( "first factorise 3a^2+7a-20
\n" ); document.write( "3a^2+12a-5a-20
\n" ); document.write( "(3a^2+12a)-(5a-20)
\n" ); document.write( "3a(a+4)-5(a+4)
\n" ); document.write( "hence the factors are
\n" ); document.write( "(3a-5)(a+4). THEN divide the factors by (a+4)
\n" ); document.write( "={(3a-5)(a+4)}/(a+4)
\n" ); document.write( "=(3a-5) because (a+4) will cancel.
\n" ); document.write( ".'. our answer is 3a-5. \n" ); document.write( "

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