document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=593737>Question 593737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use properties of logorithms to find exact value of expression. <BR>\n" );
document.write( "2log2^3-log2^7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376443 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376443\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2log2^3-log2^7<BR>\n" );
document.write( "log(2^3)^2-log2^7<BR>\n" );
document.write( "log(2^6)-log2^7<BR>\n" );
document.write( "log[(2^6)/(2^7)]<BR>\n" );
document.write( "log[1/2]<BR>\n" );
document.write( "log(1) - log(2)<BR>\n" );
document.write( "log(10^0) - log(2)<BR>\n" );
document.write( "0 - log(2)<BR>\n" );
document.write( "-log(2)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );