document.write( "Question 593730: I am just re-learning algebra after 20 years, so it's been difficult.\r
\n" );
document.write( "\n" );
document.write( "A college student earned $7300 during summer vacation working as a waiter in a popular restaurant. The student invested part of the money at 7% and the rest at 6%. If the student received a total of $458 in interest at the end of the yera, how much was invested at 7%?\r
\n" );
document.write( "\n" );
document.write( "Thank you. \n" );
document.write( "
Algebra.Com's Answer #376431 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 7.00% per annum ---x \n" ); document.write( "Part II 6.00% per annum ---y \n" ); document.write( "Sum of their investments \n" ); document.write( " \n" ); document.write( "x +y= 7300 -------------------1 \n" ); document.write( "Interest from both investments \n" ); document.write( " \n" ); document.write( "7.00% x + 6.00% y= 458 \n" ); document.write( "Multiply by 100 \n" ); document.write( "7 x + 6 y= 45800.00 --------2 \n" ); document.write( "Multiply (1) by -7 \n" ); document.write( "we get \n" ); document.write( "-7 x -7 y= -51100.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -1 y= -5300 \n" ); document.write( "divide by -1 \n" ); document.write( " y = 5300 \n" ); document.write( "Part I 6.00% $ 5300 \n" ); document.write( "Part II 7.00% $ 2000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "5300 --------- 6.00% ------- 318.00 \n" ); document.write( "2000 ------------- 7.00% ------- 140.00 \n" ); document.write( "Total -------------- 458.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |