document.write( "Question 593650: {log^3, 27 } \n" ); document.write( "
Algebra.Com's Answer #376410 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
{log^3, 27 }
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\n" ); document.write( "What does that mean?
\n" ); document.write( "The log cubed of what?
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\n" ); document.write( "After input from Thank You note:
\n" ); document.write( "\"log%28sqrt%283%29%2C27%29+=+x\"
\n" ); document.write( "If you recognize that 27 is 3^3, then 27 = (sqrt(3))^6
\n" ); document.write( "--> x = 6
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\n" ); document.write( "If you don't see that, use the base change:
\n" ); document.write( "\"x+=+log%2827%29%2Flog%28sqrt%283%29%29\"
\n" ); document.write( "x = 6
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