document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=6857>Question 6857</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If y = 39 and y = -x/4 + 15, what is the value of X? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3764 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = -x/4 + 15\r<BR>\n" );
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document.write( "39 = -x/4 + 15 --> subtract 15 from both sides<BR>\n" );
document.write( "24 = -x/4 --> multiply both sides by 4<BR>\n" );
document.write( "-x = 96 --> multiply both sides by -1<BR>\n" );
document.write( "x = -96\r<BR>\n" );
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document.write( "the final 2 steps could be done in one...multiply by -4, but i split it into 2 for sake of ease.\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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