document.write( "Question 593604: sin theta=1/2 and tan theta=-square root of 3 over 3, find sec theta \n" ); document.write( "

Algebra.Com's Answer #376386 by danarusu(2) $\"\"$ $\"About$

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What we know:
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\n" ); document.write( "\n" ); document.write( "(I): $\"tan%28theta%29+=+sin%28theta%29%2Fcos%28theta%29\"$
\n" ); document.write( "(II): $\"tan%28theta%29+=+-sqrt%283%29%2F3\"$
\n" ); document.write( "(III): $\"sin%28theta%29+=+1%2F2\"$
\n" ); document.write( "(IV): $\"cos%28theta%29%2Asec%28theta%29+=+1\"$
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\n" ); document.write( "From (I)+(II)+(III) => $\"cos%28theta%29+=+-sqrt%283%29%2F2\"$ (**)
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\n" ); document.write( "From(**)+(IV) => $\"sec%28theta%29+=+-2%2Asqrt%283%29%2F3\"$ \n" ); document.write( "

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