document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=593573>Question 593573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello,<BR>\n" );
document.write( "Could u pls help me with this:\r<BR>\n" );
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document.write( "Use the quadratic equation y = x2 + 3x – 10.<BR>\n" );
document.write( "Where does the vertex of the parabola lie?\r<BR>\n" );
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document.write( "Thanks a lot,<BR>\n" );
document.write( "   H.H </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376377 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376377\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the general vertex form is ___ y = a(x - h)^2 + k , with the vertex at (h,k)\r<BR>\n" );
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document.write( "y = 1(x^2 + 3x) - 10\r<BR>\n" );
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document.write( "completing the square ___ y = 1(x^2 + 3x + 9/4) - 10 - 9/4 ___ y =1(x + 3/2)^2 - 49/4 </SPAN>\n" );
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